Answer
$4+1+(-2)+(-5)$
$-2$
Work Step by Step
$\sum_{i=1}^4(-3x_i-2)$
$=(-3x_1-2)+(-3x_2-2)+(-3x_3-2)+(-3x_4-2)$
$=(-3*(-2)-2)+(-3*(-1)-2)+(-3*0-2)+(-3*1-2)$
$=4+1+(-2)+(-5)$
$=\boxed{-2}$
Precalculus (6th Edition)
by Lial, Margaret L.; Hornsby, John; Schneider, David I.; Daniels, Callie
Published by
Pearson
ISBN 10:
013421742X
ISBN 13:
978-0-13421-742-0
Chapter 11 - Further Topics in Algebra - 11.1 Sequences and Series - 11.1 Exercises - Page 1015: 62
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