Answer
$115$
Work Step by Step
$\sum ^{5}_{i=1}\left( 8i-1\right) =\sum ^{5}_{i=1}8i-\sum ^{5}_{i=1}1=8\times \dfrac {n\left( n+1\right) }{2}-1\times n=\dfrac {8\times 5\times \left( 5+1\right) }{2}-1\times 5=115$
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