Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 11 - Further Topics in Algebra - 11.1 Sequences and Series - 11.1 Exercises - Page 1015: 77

Answer

$1240$

Work Step by Step

$\sum ^{15}_{i=1}i^{2}=\dfrac {n\left( n+1\right) \left( 2n+1\right) }{6}=\dfrac {15\times \left( 15+1\right) \times \left( 2\times 15+1\right) }{6}=1240$
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