Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 11 - Further Topics in Algebra - 11.1 Sequences and Series - 11.1 Exercises - Page 1015: 78

Answer

$3251250$

Work Step by Step

$\sum ^{50}_{i=1}2i^{3}=2\sum ^{50}_{i=1}i^{3}=2\times \dfrac {n^{2}\times \left( n+1\right) ^{2}}{4}=\dfrac {2\times 50^{2}\times 51^{2}}{4}=3251250$
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