Answer
$-1+1+3+5+7$, $15$
Work Step by Step
$\sum_{i=1}^5(2x_i+3)$
$=(2x_1+3)+(2x_2+3)+(2x_3+3)+(2x_4+3)+(2x_5+3)$
$=(2*(-2)+3)+(2*(-1)+3)+(2*0+3)+(2*1+3)+(2*2+3)$
$=-1+1+3+5+7$
$=\boxed{15}$
Precalculus (6th Edition)
by Lial, Margaret L.; Hornsby, John; Schneider, David I.; Daniels, Callie
Published by
Pearson
ISBN 10:
013421742X
ISBN 13:
978-0-13421-742-0
Chapter 11 - Further Topics in Algebra - 11.1 Sequences and Series - 11.1 Exercises - Page 1015: 61
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