Answer
$176$
Work Step by Step
$\sum_{i=3}^6 (2i^2+1)$
$=(2*3^2+1)+(2*4^2+1)+(2*5^2+1)+(2*6^2+1)$
$=19+33+51+73$
$=176$
Precalculus (6th Edition)
by Lial, Margaret L.; Hornsby, John; Schneider, David I.; Daniels, Callie
Published by
Pearson
ISBN 10:
013421742X
ISBN 13:
978-0-13421-742-0
Chapter 11 - Further Topics in Algebra - 11.1 Sequences and Series - 11.1 Exercises - Page 1014: 50
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