Answer
$254$
Work Step by Step
$\sum_{i=1}^4(i^4-i^3)$
$=(1^4-1^3)+(2^4-2^3)+(3^4-3^3)+(4^4-4^3)$
$=0+8+54+192$
$=\boxed{254}$
Precalculus (6th Edition)
by Lial, Margaret L.; Hornsby, John; Schneider, David I.; Daniels, Callie
Published by
Pearson
ISBN 10:
013421742X
ISBN 13:
978-0-13421-742-0
Chapter 11 - Further Topics in Algebra - 11.1 Sequences and Series - 11.1 Exercises - Page 1014: 54
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