Answer
$A_{1}=3;a_{2}=9;a_{3}=15;a_{4}=21;a_{5}=27$
Work Step by Step
$a_{1}=6\times 1-3=3;$
$a_{2}=6\times 2-3=9;$
$a_{3}=6\times 3-3=15;$
$a_{4}=6\times 4-3=21;$
$a_{5}=6\times 5-3=27$
Precalculus (6th Edition)
by Lial, Margaret L.; Hornsby, John; Schneider, David I.; Daniels, Callie
Published by
Pearson
ISBN 10:
013421742X
ISBN 13:
978-0-13421-742-0
Chapter 11 - Further Topics in Algebra - 11.1 Sequences and Series - 11.1 Exercises - Page 1014: 12
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