Answer
$700$
Work Step by Step
$\sum ^{4}_{k=1}\left( k+1\right) ^{k}=\left( 1+1\right) ^{1}+\left( 2+1\right) ^{2}+\left( 3+1\right) ^{3}+\left( 4+1\right) ^{4}=2+9+64+625=700$
Precalculus (6th Edition)
by Lial, Margaret L.; Hornsby, John; Schneider, David I.; Daniels, Callie
Published by
Pearson
ISBN 10:
013421742X
ISBN 13:
978-0-13421-742-0
Chapter 11 - Further Topics in Algebra - 11.1 Sequences and Series - 11.1 Exercises - Page 1014: 42
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