Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 11 - Further Topics in Algebra - 11.1 Sequences and Series - 11.1 Exercises: 42

Answer

$700$

Work Step by Step

$\sum ^{4}_{k=1}\left( k+1\right) ^{k}=\left( 1+1\right) ^{1}+\left( 2+1\right) ^{2}+\left( 3+1\right) ^{3}+\left( 4+1\right) ^{4}=2+9+64+625=700$
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