Answer
$d_{1}=\dfrac {6}{5};a_{2}=\dfrac {7}{6};a_{3}=\dfrac {8}{7};a_{4}=\dfrac {9}{8};a_{5}=\dfrac {10}{9}$
Work Step by Step
$9_{1}=\dfrac {1+5}{1+4}=\dfrac {6}{5};$
$a_{2}=\dfrac {2+5}{2+4}=\dfrac {7}{6};$
$a_{3}=\dfrac {3+5}{3+4}=\dfrac {8}{7};$
$a_{4}=\dfrac {4+5}{4+4}=\dfrac {9}{8};$
$a_{5}=\dfrac {5+5}{5+4}=\dfrac {10}{9}$
