Answer
$30$
Work Step by Step
$\sum_{i=1}^3(i^3-i)$
$=(1^3-1)+(2^3-2)+(3^3-3)$
$=0+6+24$
$=\boxed{30}$
Precalculus (6th Edition)
by Lial, Margaret L.; Hornsby, John; Schneider, David I.; Daniels, Callie
Published by
Pearson
ISBN 10:
013421742X
ISBN 13:
978-0-13421-742-0
Chapter 11 - Further Topics in Algebra - 11.1 Sequences and Series - 11.1 Exercises - Page 1014: 53
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