Answer
$-2$
Work Step by Step
$\sum_{i=1}^4[(-2)^i-3]$
$=[(-2)^1-3]+[(-2)^2-3]+[(-2)^3-3]+[(-2)^4-3]$
$=-5+1+(-11)+13$
$\boxed{=-2}$
Precalculus (6th Edition)
by Lial, Margaret L.; Hornsby, John; Schneider, David I.; Daniels, Callie
Published by
Pearson
ISBN 10:
013421742X
ISBN 13:
978-0-13421-742-0
Chapter 11 - Further Topics in Algebra - 11.1 Sequences and Series - 11.1 Exercises - Page 1014: 52
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