Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 4 - Section 4.6 - Complex Fractions and Review of Order of Operations - Exercise Set: 36

Answer

$\frac{2}{9}$

Work Step by Step

When $x=-\frac{1}{3}$ and $z=\frac{5}{6}$: $(1-x)(1-x)$ $=[1-(-\frac{1}{3})][1-(\frac{5}{6})]$ $=(1+\frac{1}{3})(1-\frac{5}{6})$ $=(\frac{3}{3}+\frac{1}{3})(\frac{6}{6}-\frac{5}{6})$ $=\frac{4}{3}\times\frac{1}{6}$ $=\frac{2}{3}\times\frac{1}{3}$ $=\frac{2}{9}$
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