Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 4 - Section 4.6 - Complex Fractions and Review of Order of Operations - Exercise Set: 24

Answer

$\frac{16}{27}$

Work Step by Step

$(\frac{8}{9})^{2}\div(2-\frac{2}{3})$ $=(\frac{8}{9}\times\frac{8}{9})\div(\frac{6}{3}-\frac{2}{3})$ $=\frac{64}{81}\div\frac{4}{3}$ $=\frac{64}{81}\times\frac{3}{4}$ $=\frac{16}{27}\times\frac{1}{1}$ $=\frac{16}{27}$
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