Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 4 - Section 4.6 - Complex Fractions and Review of Order of Operations - Exercise Set: 30

Answer

$2$

Work Step by Step

When $x=-\frac{1}{3}$ and $z=\frac{5}{6}$: $2z-x$ $=(2\times\frac{5}{6})-(-\frac{1}{3})$ $=(\frac{2}{1}\times\frac{5}{6})+\frac{1}{3}$ $=(\frac{1}{1}\times\frac{5}{3})+\frac{1}{3}$ $=\frac{5}{3}+\frac{1}{3}$ $=\frac{6}{3}$ $=2$
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