Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 4 - Section 4.6 - Complex Fractions and Review of Order of Operations - Exercise Set: 15

Answer

$3\frac{8}{9}$

Work Step by Step

$2^{2}-(\frac{1}{3})^{2}$ $=4-\frac{1}{9}$ $=\frac{36}{9}-\frac{1}{9}$ $=\frac{35}{9}$ $=3\frac{8}{9}$
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