Chapter 4 - Section 4.6 - Complex Fractions and Review of Order of Operations - Exercise Set - Page 284: 35

$1\frac{2}{9}$

When $x=-\frac{1}{3}$ and $z=\frac{5}{6}$: $(1+x)(1+z)$ $=[1+(-\frac{1}{3})][1+(\frac{5}{6})]$ $=(1-\frac{1}{3})(1+\frac{5}{6})$ $=(\frac{3}{3}-\frac{1}{3})(\frac{6}{6}+\frac{5}{6})$ $=\frac{2}{3}\times\frac{11}{6}$ $=\frac{1}{3}\times\frac{11}{3}$ $=\frac{11}{9}$ $=1\frac{2}{9}$