Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 4 - Section 4.6 - Complex Fractions and Review of Order of Operations - Exercise Set - Page 284: 42

Answer

$\frac{15}{16}$

Work Step by Step

$(-\frac{3}{4})^{2}+\frac{3}{8}$ $=(-\frac{3}{4})(-\frac{3}{4})+\frac{3}{8}$ $=--(\frac{3}{4}\times\frac{3}{4})+\frac{3}{8}$ $=\frac{3}{4}\times\frac{3}{4}+\frac{3}{8}$ $=\frac{9}{16}+\frac{3}{8}$ $=\frac{9}{16}+\frac{6}{16}$ $=\frac{15}{16}$
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