Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 4 - Section 4.6 - Complex Fractions and Review of Order of Operations - Exercise Set: 22

Answer

$\frac{4}{5}$

Work Step by Step

$\frac{2}{5}\times(5-\frac{1}{2})-1$ $=\frac{2}{5}\times(\frac{10}{2}-\frac{1}{2})-1$ $=\frac{2}{5}\times\frac{9}{2}-1$ $=\frac{1}{5}\times\frac{9}{1}-1$ $=\frac{9}{5}-1$ $=\frac{9}{5}-\frac{5}{5}$ $=\frac{4}{5}$
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