Answer
$53$
Work Step by Step
The expanded form of $110101_{\text{two}}$ is:
$=(1 \times 2^5) + (1 \times 2^4)+(0 \times 2^3) + (1 \times 2^2) + (0 \times 2^1) + (1 \times 1)
\\=(1\times 32) + (1\times 16) + 0+(1 \times 4)+0+1
\\=32+16+4+1
\\=53$