Answer
$1442_{\text{six}}$
Work Step by Step
The place values of base six are: $...,6^4, 6^3, 6^2, 6^1, 1$.
The place values that are less than or equal to $386$ are $6^3$, $6^2$, $6^1$, and $1$
Divide $386$ by $6^3$ or $216$ to obtain:
$386 \div 216 = 1$ remainder $170$
Divide the remainder $1701$ by $6^2$ or $36$ to obtain:
$170 \div 36 = 4$ remainder $26$
Divide the remainder $26$ by $6^1$ or $6$ to obtain:
$26 \div 6 = 4$ remainder $2$
Divide the remainder $2$ by $1$ to obtain:
$2\div 1 = 2$ remainder $0$
Thus,
$386=(1 \times 6^3) + (4 \times 6^2) + (4 \times 6^1) + (2 \times 1)
\\386=1442_{\text{six}}$
