Thinking Mathematically (6th Edition)

Published by Pearson
ISBN 10: 0321867327
ISBN 13: 978-0-32186-732-2

Chapter 4 - Number Representation and Calculation - 4.2 Number Bases in Positional Systems - Exercise Set 4.2 - Page 226: 12

Answer

$5,582$

Work Step by Step

The expanded form of $41502_{\text{six}}$ is: $=(4 \times 6^4) + (1 \times 6^3) + (5\times 6^2)+(0 \times 6^1) + (2 \times 1) \\=(4\times 1296) + (1 \times 216) + (5 \times 36)+0+2 \\=5184+216+180+2 \\=5,582$
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