Answer
$455$
Work Step by Step
The expanded form of $2035_{\text{six}}$ is:
$=(2 \times 6^3) + (0\times 6^2)+(3 \times 6^1) + (5 \times 1)
\\=(2\times 216) + 0 + (3 \times 6)+5
\\=4322 +18 +5
\\=455$
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