Thinking Mathematically (6th Edition)

Published by Pearson
ISBN 10: 0321867327
ISBN 13: 978-0-32186-732-2

Chapter 4 - Number Representation and Calculation - 4.2 Number Bases in Positional Systems - Exercise Set 4.2: 14

Answer

$10,354$

Work Step by Step

The expanded form of $3104_{\text{fifteen}}$ is: $=(3 \times 15^3) + (1 \times 15^2) + (0 \times 15^1) + (4 \times 1) \\=(3\times 3375) + (1\times 225) + 0+4 \\=10,125+225+4 \\=10,354$
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