Answer
$101_{\text{six}}$
Work Step by Step
The place values of base six are: $,,,, 6^3, 6^2, 6^1, 1$.
The place value that are less than or equal to $37$ are $6^2$, $6^1$, and $1$
Divide $37$ by $6^2$ or $36$ to obtain:
$37 \div 36 = 1$ remainder $1$
Divide the remainder $1$ by $6^1$ to obtain:
$1 \div 6^1 = 0$ remainder $1$
Divide the remainder $1$ by $1$ to obtain:
$1 \div 1 = 1$ remainder $0$
Thus,
$37=(1 \times 6^2) + (0 \times 6^1) + (1 \times 1)
\\37=101_{\text{six}}$
