Answer
$y' = e^{-x}secx(xtanx -x +1)$
Work Step by Step
$y = xe^{-x}secx$
$y = e^{-x}(x\ secx)$
$y' = -e^{x}(x\ secx) + e^{-x}(secx + x\ secx\ tanx)$
$y' = -e^{-x}\ x\ secx +e^{-x}secx + e^{-x}\ x\ secx\ tanx$
$y' = e^{-x}secx(xtanx -x +1)$
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