University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 3 - Section 3.5 - Derivatives of Trigonometric Functions - Exercises - Page 151: 5

Answer

$y' = -cosecx\ cotx -\frac{2}{\sqrt x} -\frac{7}{e^{x}}$

Work Step by Step

$y = cosecx -4\sqrt x + \frac{7}{e^{x}}$ $y' = -cosecx\ cotx -\frac{2}{\sqrt x} -\frac{7}{e^{x}}$
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