Answer
$\displaystyle y' = (xsinx +cosx) (\frac{-1}{x^{2}}+\frac{1}{cos^{2}x})$
Work Step by Step
$\displaystyle y = \frac{cosx}{x} + \frac{x}{cosx}$
$\displaystyle y' = \frac{-xsinx - cosx}{x^{2}} + \frac{cosx + xsinx}{cos^{2}x}$
$\displaystyle y' = (xsinx +cosx) (\frac{-1}{x^{2}}+\frac{1}{cos^{2}x})$
