Answer
$r' = -\theta (2 sin\theta + \theta cos\theta)$
Work Step by Step
$r = 4-\theta ^{2}sin\theta $
$r' = 0- (2\theta sin\theta + \theta^{2}cos\theta)$
$r' = -\theta (2 sin\theta + \theta cos\theta)$
University Calculus: Early Transcendentals (3rd Edition)
by Hass, Joel R.; Weir, Maurice D.; Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0321999584
ISBN 13:
978-0-32199-958-0
Chapter 3 - Section 3.5 - Derivatives of Trigonometric Functions - Exercises - Page 151: 23
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