Answer
$y' = -cosecx(cosec^{2}x +cot^{2}x)$
Work Step by Step
$y = \frac{cosx}{sin^{2}x}$
$y = cotx\ cosecx$
$y' = -cosec^{2}x\ cosecx - cotx\ (cosecx\ cotx)$
$y' = -cosec^{3}x- cot^{2}{x}\ cosecx$
$y' = -cosecx(cosec^{2}x +cot^{2}x)$
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