University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 3 - Section 3.5 - Derivatives of Trigonometric Functions - Exercises - Page 151: 2

Answer

$y' = \frac{-3}{x^{2}} + 5cosx$

Work Step by Step

$y = \frac{3}{x} + 5sinx$ $y' = \frac{-3}{x^{2}} + 5cosx$
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