Answer
$\displaystyle p' = \frac{q*sec^{2}q -tanq(3q^{2}+1+qtanq)}{q^{2}secq}$
Work Step by Step
$\displaystyle p = \frac{3q+tanq}{qsecq}$
$\displaystyle p' = \frac{qsecq(3+sec^{2}q) - (3q+tanq)(secq+qsecqtanq)}{q^{2}sec^{2}q}$
$\displaystyle p' = \frac{q*sec^{3}q -3q^{2}secq*tanq - tanq*secq- qsecq*tan^{2}q}{q^{2}sec^{2}q}$
$\displaystyle p' = \frac{q*sec^{2}q -tanq(3q^{2}+1+qtanq)}{q^{2}secq}$
