Multivariable Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 0-53849-787-4
ISBN 13: 978-0-53849-787-9

Chapter 11 - Infinite Sequences and Series - 11.1 Exercises - Page 724: 5

Answer

{$\frac{1}{5}$, $-\frac{1}{25}$, $\frac{1}{125}$, $-\frac{1}{625}$, $\frac{1}{3125}$}

Work Step by Step

Plug in $n = 1:$ $a_1 =$ $\frac{(-1)^0}{5^1}$ $= $$\frac{1}{5}$ Plug in $n=2:$ $a_2 = $ $\frac{(-1)^{2-1}}{5^2}$ $= $$-\frac{1}{25}$ Doing the same for $n = 3, 4, 5$, we obtain $a_3 = $ $\frac{1}{125}$ $a_4 = $ $-\frac{1}{625}$ $a_5 = $ $\frac{1}{3125}$ And so, the first five terms of the sequence are $:$ {$\frac{1}{5}$, $-\frac{1}{25}$, $\frac{1}{125}$, $-\frac{1}{625}$, $\frac{1}{3125}$}
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