Multivariable Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 0-53849-787-4
ISBN 13: 978-0-53849-787-9

Chapter 11 - Infinite Sequences and Series - 11.1 Exercises - Page 724: 38

Answer

Converges to $1$

Work Step by Step

We can write $\ln{2n}$ as $\ln{2} + \ln{n}$. Hence: $$a_n = \frac{\ln{n}}{\ln{2} + \ln{n}} = \frac{1}{\frac{\ln{2}}{\ln{n}} + 1}.$$ Since the fraction in the denominator approaches 0 as $n \to \infty$, our sequence converges to $\frac{1}{0 + 1} = 1$.
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