Answer
Converges to $e^2$.
Work Step by Step
By the continuity of limits, we may take the limit to the exponent of $e$. The limit of $\frac{2n}{n + 2}$ is 2. Hence, the sequence converges to $e^2.$
Multivariable Calculus, 7th Edition
by Stewart, James
Published by
Brooks Cole
ISBN 10:
0-53849-787-4
ISBN 13:
978-0-53849-787-9
Chapter 11 - Infinite Sequences and Series - 11.1 Exercises - Page 724: 32
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