Answer
$a_{n}=3n+2$, n goes from 1 to $\infty$.
Work Step by Step
{$5, 8, 11, 14, 17,~ ...$}
$a_{2}-a_{1}=3,~a_{3}-a_{2}=3$. And so on.
$a_{2}=a_{1}+3$
$a_{3}=a_{2}+3=a_{1}+2\times3$
$a_{4}~=a_{3}+3=a_{1}+3\times3$, ...
$a_{n}=a_{1}+3(n-1)$
$a_{n}=5+3(n-1)=3n+2$
