Multivariable Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 0-53849-787-4
ISBN 13: 978-0-53849-787-9

Chapter 11 - Infinite Sequences and Series - 11.1 Exercises - Page 724: 7

Answer

$a_{1}=\frac{1}{2!}=\frac{1}{2}$ $a_{2}=\frac{1}{3!}=\frac{1}{6}$ $a_{3}=\frac{1}{4!}=\frac{1}{24}$ $a_{4}=\frac{1}{5!}=\frac{1}{120}$ $a_{5}=\frac{1}{6!}=\frac{1}{720}$

Work Step by Step

$a_{1}=\frac{1}{1+1!}=\frac{1}{2!}$ $a_{2}=\frac{1}{2+1!}=\frac{1}{3!}$ $a_{3}=\frac{1}{3+1!}=\frac{1}{4!}$ $a_{4}=\frac{1}{4+1!}=\frac{1}{5!}$ $a_{5}=\frac{1}{5+1!}=\frac{1}{6!}$
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