Finite Math and Applied Calculus (6th Edition)

Published by Brooks Cole
ISBN 10: 1133607705
ISBN 13: 978-1-13360-770-0

Chapter 0 - Section 0.2 - Exponents and Radicals - Exercises - Page 16: 53

Answer

$\sqrt {(-2)^2} = 2$

Work Step by Step

By the formula on page 11, $\sqrt {(-2)^2} = \sqrt {(-2)\times(-2)} = \sqrt 4 = \sqrt {2^2} = 2$.
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