Finite Math and Applied Calculus (6th Edition)

Published by Brooks Cole
ISBN 10: 1133607705
ISBN 13: 978-1-13360-770-0

Chapter 0 - Section 0.2 - Exponents and Radicals - Exercises - Page 16: 46

Answer

$$1$$

Work Step by Step

$$\sqrt 25 - \sqrt 16$$ 1. First take the square root of 25 and the square root of 16. $$\sqrt 25 = 5$$ $$\sqrt 16 =4$$ 2. Then using BEDMAS, subtract 5 from 4 to get 1 as the final answer. $$5-4=1$$
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