Finite Math and Applied Calculus (6th Edition)

Published by Brooks Cole
ISBN 10: 1133607705
ISBN 13: 978-1-13360-770-0

Chapter 0 - Section 0.2 - Exponents and Radicals - Exercises - Page 16: 27

Answer

$(\frac{xy^{-2}z}{x^{-1}z})^3 = \frac{x^6}{y^6}$

Work Step by Step

By the formulas given on page eight and nine, $(\frac{xy^{-2}z}{x^{-1}z})^3 = \frac{(xy^{-2}z)^3}{(x^{-1}z)^3} = \frac{x^3y^{-6}z^3}{x^{-3}z^3} = x^{3-(-3)}y^{-6}z^{3-3} = x^6y^{-6}z^0 = x^6y^{-6} = \frac{x^6}{y^6}$.
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