Finite Math and Applied Calculus (6th Edition)

Published by Brooks Cole
ISBN 10: 1133607705
ISBN 13: 978-1-13360-770-0

Chapter 0 - Section 0.2 - Exponents and Radicals - Exercises - Page 16: 57

Answer

$\sqrt {a^2b^2} = ab$

Work Step by Step

By the formula in page 11, $\sqrt {a^2b^2} = \sqrt {a^2} \sqrt {b^2}$ Because a and b are positive numbers, $\sqrt {a^2} = a$ and $\sqrt {b^2} = b$. Therefore, $\sqrt {a^2b^2} = \sqrt {a^2} \sqrt {b^2} = ab$.
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