Finite Math and Applied Calculus (6th Edition)

Published by Brooks Cole
ISBN 10: 1133607705
ISBN 13: 978-1-13360-770-0

Chapter 0 - Section 0.2 - Exponents and Radicals - Exercises - Page 16: 35

Answer

$1 - \frac{0.3}{x^{-2}} - \frac{6}{5} x^{-1} = 1 - 0.3x^2 - \frac{6}{5x}$

Work Step by Step

By the formula given on page eight , $1 - \frac{0.3}{x^{-2}} - \frac{6}{5} x^{-1} = 1 - \frac{0.3}{\frac{1}{x^2}} - \frac{6}{5}\times\frac{1}{x} = 1 - 0.3x^2 - \frac{6}{5x}$.
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