Finite Math and Applied Calculus (6th Edition)

Published by Brooks Cole
ISBN 10: 1133607705
ISBN 13: 978-1-13360-770-0

Chapter 0 - Section 0.2 - Exponents and Radicals - Exercises - Page 16: 56

Answer

$\sqrt {\frac{1}{9}(3+33)} = 2$

Work Step by Step

$\sqrt {\frac{1}{9}(3+33)} = \sqrt {\frac{1}{9}\times36} = \sqrt {4} = \sqrt {2^2} = 2$
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