Finite Math and Applied Calculus (6th Edition)

Published by Brooks Cole
ISBN 10: 1133607705
ISBN 13: 978-1-13360-770-0

Chapter 0 - Section 0.2 - Exponents and Radicals - Exercises - Page 16: 71

Answer

$\frac{x^2}{\sqrt x} = x^{1.5}$

Work Step by Step

$\frac{x^2}{\sqrt x} = \frac{x^2}{x^{0.5}} = x^{2 - 0.5} = x^{1.5}$
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