Answer
As a result $\frac{4}{7}\langle6,2,-3\rangle$ is a vector in the same direction as $\langle 6,2,-3\rangle$ with a length of $4$.
Work Step by Step
We are given the vector $\langle6,2,-3\rangle$. In order to get a vector in the same direction with a length of $4$ we can simply divide by the length of the given vector and multiply by $4$.
$|\langle6,2,-3\rangle|=\sqrt{(6)^2+(2)^2+(-3)^2}=\sqrt{49}=7\Rightarrow \frac{4}{7}\langle6,2,-3\rangle$
