Answer
$a+b=\lt6,3\gt$
$4a+2b=\lt6,14\gt$
$|a|=\sqrt{25}$
$|a-b|=13$
Work Step by Step
$a+b=\lt6,3\gt$
$4a+2b=(4)+(2<9,-1>)=\lt6,14\gt$
$|a|=\sqrt{(-3)^2+(4)^2}=\sqrt{25}$
$|a-b|=\sqrt {(-3-9)^2+(4+1)^2}=13$
Calculus: Early Transcendentals 8th Edition
by Stewart, James
Published by
Cengage Learning
ISBN 10:
1285741552
ISBN 13:
978-1-28574-155-0
Chapter 12 - Section 12.2 - Vectors - 12.2 Exercises - Page 805: 19
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