Answer
As a result $\frac{1}{9}\langle8,-1,4\rangle$ is a unit vector in the direction of $\langle8,-1,4\rangle$.
Work Step by Step
We are given the vector $\langle8,-1,4\rangle$. In order to get a unit vector with the same direction we can simply divide by the length of the vector: $|\langle8,-1,4\rangle|=\sqrt{(8)^2+(-1)^2+(4)^2}=\sqrt{81}=9\Rightarrow\frac{1}{9}\langle8,-1,4\rangle$
