Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 12 - Section 12.2 - Vectors - 12.2 Exercises - Page 805: 8

Answer

$\sqrt 2$

Work Step by Step

$u=-\frac{1}{\sqrt 2}i+\frac{1}{\sqrt 2}j$ $v=-\frac{1}{\sqrt 2}i-\frac{1}{\sqrt 2}j$ $u+v=-\frac{2}{\sqrt 2}i$ let $w= |w|i$ $u+v+w=0$ (given) $-\frac{2}{\sqrt 2}i+ |w|i=0$ $|w|i=\frac{2}{\sqrt 2}i$ Hence, $|w|=\frac{2}{\sqrt 2} \times \frac{\sqrt 2}{\sqrt 2}=\sqrt 2$
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