Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 12 - Section 12.2 - Vectors - 12.2 Exercises - Page 805: 4

Answer

(a) $\vec {AC}$ (b) $\vec {CB}$ (c) $\vec {DA}$ (d) $\vec {DB}$

Work Step by Step

(a) The triangle rule states that if A,B and C form a triangle then $ \vec {AB}+\vec {BC}=\vec {AC}$. In this case A,B and C form a triangle . Moving from A to B and then from B to C produces the same result as moving directly from A to C. (b) The triangle rule states that if A,B and C form a triangle then $ \vec {AB}+\vec {BC}=\vec {AC}$. In this case C,D and B form a triangle . Moving from C to D and then from D to B produces the same result as moving directly from C to B. Thus, $ \vec {CD}+\vec {DB}=\vec {CB}$ (c) The triangle rule states that if A,B and C form a triangle then $ \vec {AB}+\vec {BC}=\vec {AC}$. As we know: $\vec {AB}=-\vec {BA}$ (basic vector algebra) Thus, $ \vec {DB}-\vec {AB}=\vec {DB}+\vec {BA}=\vec {DA}$ (d) Add the first two vectors to get the result $\vec {DA}$ $ \vec {DC}+\vec {CA}=\vec {DA}$ Add the third vector to get the result $\vec {DB}$ $ \vec {DA}+\vec {AB}=\vec {DB}$ This is equivalent to $(\vec {DC}+\vec {CA})+\vec {AB}=\vec {DB}$
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