Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 8 - Sequences and Infinite Series - 8.2 Sequences - 8.2 Exercises: 19

Answer

$\{5(-1.01)^n\}$ diverges and oscillates.

Work Step by Step

The general form of a geometric sequence is $a^r$. For the sequence $\{5(-1.01)^n\}$, we can ignore the $5$ because it's a constant and is not affected by $n$. $|a| \geq 1$, meaning that the sequence diverges. Due to the negative sign in $a$, the sequence also oscillates.
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